What are the zeros of the function?

f(t)=t^2−13t+36

enter your answers in the boxes.

For this case, the first thing you should do is factor the expression correctly.
 We have then:
 f (t) = t ^ 2-13t + 36
 We are looking for two numbers that add -13 and multiply den as results 36:
 f (t) = (t-9) * (t-4)
 Thus, the zeros of the function are:
 t1 = 9
 t2 = 4
  
 t1 = 9 
 t2 = 4

Ithink it should be 55.