Mathematics, 29.07.2019 04:30, kloeydrea08
Me the perimeter of a rectangle is 141 feet, and the length is twice the width. what are the dimensions of the rectangle? what's the width of the rectangle and what's the length?
Answers: 1
answered: Guest
option a, c,d are correct.
step-by-step explanation:
from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have
tz=sz(given)
bz=zb(common)
therefore, by rhs rule,δtzb ≅δszb
by cpctc, sz≅tz
also, from δctz and δasz,
tz=sz(given)
∠tcz=∠saz(90°)
by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz
also,from δasz and δzsb,
zs=sz(common)
∠zbs=∠saz=90°
by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb
hence, option a, c,d are correct.
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Me the perimeter of a rectangle is 141 feet, and the length is twice the width. what are the dimensi...
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