In a statistics class there are 11 juniors and 6 seniors; 2 of the seniors are females; 6 of the juniors are males. if a student is selected at random, what is the probability that the student is either a junior or a female? enter your answer as a fully reduced fraction.

Step-by-step explanation:

Given: Number of juniors = n(J)= 11

Number of seniors = 6

Total students n(S)=

Number of seniors are which are females =2

Number of  juniors are which are males =6

Then, number of juniors which are females =

Now, total females n(F)=

such that number of juniors which are females n(J∩F) =

Now, the number of students either a junior or a female is given by :_

Now, the probability that the student is either a junior or a female is given by :-

x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

step-by-step explanation:

last month maria hiked the 5-mile mountain trail a number of times and she hiked the 10-mile canal trail several times. let x represent the number of times she hiked the 5-mile trail, and let y represent the number of times she hiked the 10-mile trail. if she hiked a total of 90 miles, which equation can be used to find the number of times maria hiked each trail? x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x