So sorry, i just don’t understand this i’m almost done.

It is worked exactly the same way your other problem was worked.
link

Atrap = (1/2)*(9+5)*5 = 35
Arect = 5*(9 +5 +5 +6.4) = 127
Atot = 127 +2*35 = 197 . . . . in^2

1. 0.3 •4 is the same as 4 groups of 0.32. 7•0.8 is the same as 7 groups of 0.83. it increases by 0.5 every time, so 0.5x4 it increases by 0.9 every time, so 0.9x5. 0.9•12=10.86. 0.47•5=2.35i can finish the next ones in a separate post