Jon is making a scale drawing to enlarge a picture. the original dimensions of the picture are 8 inches wide by 64 inches long. which of these dimensions represents a possible width and length of the enlargement? a) 1 inch wide by 8 inches long b) 8 inches long by 16 inches wide c) 16 inches wide by 128 inches long d) 128 inches wide by 16 inches long

C) Width = 16 inch, Length = 128 inches  

Step-by-step explanation:

We are given the following information in the question:

The dimension of the original picture is:

Width = 8 inches

Length = 64 inches

We have to find a possible pair of dimension such that it shows a enlarged form of our picture that is larger width and length.

a) Length = 1 inches, Width = 8 inch

This is clearly a smaller version of the original picture.

b) Length = 8 inches, Width = 16 inch

In this we have a shorter length than the original picture.

c) Length = 128 inches, Width = 16 inch

As we can see the length as well width in this option is greater than that of the original picture. Hence, this a possible pair of dimension that can shoe picture enlargement. The length and the width is twice the original picture.

d) Length = 16 inches, Width = 128 inch

Since, the length of this picture is smaller as compared to the original picture, this dimension cannot correspond to enlarged picture.

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.