A0.149-kilogram baseball, initially moving at 15 meters per second, is brought to rest in 0.040 seconds by a baseball glove on a catchers hand. the magnitude of the average force exerted on the ball by glove is

Using the relationship between force and acceleration, the average force exerted on the ball by the glove is :55.875 N

Given the Parameters :

Recall :

Force = (mΔv ÷ t)

Inputting the Values into the equation :

Force = [0.149 × (15 - 0)] ÷ 0.040

Force = (0.149 × 15) ÷. 0.040

Force = 2.235 ÷ 0.040

Force = 55.875 N

Therefore, the force exerted is 55.875 N

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8121 because

130,000 divided by 16 is 8121

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47