The back-to-back stem-and-leaf plot below shows the ages of patients seen by two doctors in a family clinic in one day. compare the ages of patients of doctor 1 and doctor 2 using the mean and the median of each data set. doctor 1 doctor 2 | 3 | 5 9 2 0 | 2 | 0 0 2 3 6 8 7 5 | 1 | 3 7 9 7 3 2 1 1 | 0 | 2 2 3 9

First let's list the list the ages of the patients for each doctor. in a stem and leaf plot the number in the middle is the stem (here the first digit of the ages) and the numbers to each side the leaves (here the second digit of the ages). the numbers at left are for doctor 1 and the ones at right for doctor 2.let's look at the second line of numbers. it looks like this: 9, 2, 0 | 2| 0, 0, 2, 3, 69, 2, 0 are the leaves for the stem 2 pertaining to doctor 1. these ages are: 20, 22, and 29.0, 0, 2, 3, 6, are the leaves for the stem 2 pertaining to doctor 2. these ages are: 20, 20,22, 23, 26.using a similar approach we list the ages of the patients for both doctors as follows. notice that the first line has a stem of 3 but only a leaf on doctor 2's side so doctor 1 has no patient that is in their 30'sdoctor 1: 29, 22, 20, 18, 17, 15, 9, 7, 3, 2, 1, 1doctor 2: 35, 26, 23, 22, 20, 20, 17, 13, 2, 2, 3, 9the median of each set of ages is the middle age when the ages are arranged in order. if two ages are in the middle (as is the case here since there are an even number of ages) we take the mean of the two (add them and divide by 2) and that is the median.doctor 1 median = (15+9)/2 = 12doctor 2 median = (17+20)/2 = 18.5the mean of the ages is obtained by adding up all the ages and dividing by the number of ages (here 12).doctor 1 mean = =11. (here the 6s repeat without end so you can write 11.16 and put a little line over the 6 to show the repetition)doctor 2 mean = =16it seems that doctor 2's patients are slightly older on average than doctor 1s as evidence by the mean and medians just found.

Here for a good time of free question aha