Shiloh has to earn at least $200 to meet her fundraising goal. she has only 100 cakes that she plans to sell at 5 dollars each. which inequality shows the number of cakes, x, shiloh can sell to meet her goal? 20 ≤ x ≤ 200 40 ≤ x ≤ 100 100 ≤ x ≤ 200 20 ≤ x ≤ 100 you in advance. ~micah k.,

The answer would be B because 200/5=40 so it would be 40<x<100

40 <= x =<100 inequality shows the right answer. Explanation:- Since she has to reach the $200 mark by selling cakes at the rate of $5 each. So, the minimum number of cakes should be 200/5 which is equals to 40. Hence minimum value of number of cakes (x) = 40 It is given that She has 100 cakes this implies that maximum value of x can be 100. hence X can be any value between 40 to 100 both inclusive.