Abag contains 9 marbles: 5 are green, 2 are red, and 2 are blue. trey chooses a marble at random, and without putting it back, chooses another one at random. what is the probability that both marbles he chooses are green? write your answer as a fraction in simplest form.

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

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