Can you check my answer? which of the following is an example of why irrational numbers are 'not' closed under addition? √4 + √4 = 2 + 2 = 4, and 4 is not irrantonal 1/2 + 1/2 = 1, and 1 is not irrational √10 + (-√10) = 0, and 0 is not irrational -3 + 3 = 0, and 0 is not irrational i was thinking: –3 + 3 = 0, and 0 is not irrational because it came up with a different number besides 3.,

-3+3 = 0 is an example of adding two rational numbers to get another rational number.

-3 = -3/1
3 = 3/1
0 = 0/1
each can be written as a fraction of whole numbers, so that's why they are rational

The actual answer is choice C

We are adding the square root of 10, written sqrt(10) in shorthand, to the negative version of the same number. Doing so leads to 0. This is using the property x + (-x) = 0. The left hand side of choice C has two irrational numbers. They add to 0 on the right hand side which is rational. The fact that we added two irrational numbers to get an rational result indicates that irrational numbers are not closed under addition.

Figure it out your self