Iwill give ! write an equation of a parabola with the given vertex and focus? vertex (-2,5) focus (-2,6) and show ur work : )

as the vertex  (−2,5)  and focus  (−2,6)  share same abscissa i.e.  −2, parabola has axis of symmetry as  x=−2  or  x+2=0

hence, equation of parabola is of the type  (y−k)=a(x−h)2, where  (h,k)  is vertex. its focus then is  (h,k+14a)

as vertex is given to be  (−2,5), the equation of parabola is

y−5=a(x+2)2

and its focus is  (−2,5+14a)

therefore  5+14a=6  or  14a=1  i.e.  a=14

and equation of parabola is  y−5=14(x+2)2

or  4y−20=(x+2)2=x2+4x+4

or  4y=x2+4x+24

so is it a b c or d

step-by-step explanation:

i think this could be a possible answer (1 / 84) -1

good luck! : d

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.