What is the sum of the polynomials (7x^3-4x^2)+(2x^3-4x^2)

Your answer is...
The problem to solve is:

(7x^3-4x^2)+(2x^3-4x^2)

Multiply the exponent of x by 3giving The answer is x3 x^3 evaluates to x3 Multiply x3 and 7 Multiply x3 and 1 The x3 just gets copied along. The answer is x3
x3
7*x^3 evaluates to 7x3 Multiply the exponent of x by 2giving 2x The answer is 2x x^2 evaluates to 2x Multiply 2x and 4 Multiply and 1 The 2x just gets copied along. The answer is 2x 4*x^2 evaluates to 7*x^3-4*x^2 evaluates to4x2 Multiply the exponent of x by 3giving The answer is x^3 evaluates to 7x3  -4x2 Multiply x3 and 2 Multiply x3 and 1 The x3 just gets copied along. The answer is x3
x3
2*x^3 evaluates to2x3 Multiply the exponent of x by 2giving The answer is x2 x^2 evaluates to 2x3 Multiply x2 and 4 Multiply x2 and 1 The  x2 just gets copied along. The answer is x2
x2
4*x^2 evaluates to 4x2 2*x^3-4*x^2 evaluates to2x3  -4x2 To add the polynomials 7x3 -4x2 and 2x3 -4x2 we try to add or combine terms in one polynomialwith any like terms in the other polynomial. 7x3+2x3 =9x3 -4x2+-4x2 =-8x2 The answer is 9x3 -8 2 (7*x^3-4*x^2)+(2*x^3-4*x^2) evaluates to9x3 -8x2 The final answer is 9x3  -8 2
Hope this helps!:)
Took m FOREVER but I got it done!
@SamSamySamantha