Four times the larger of two numbers is equal to seven times the smaller. the sum of the numbers is 22. what are the numbers?

The larger is 14 the smaller is 8

Let the larger number be L and the smaller be S
So we know that

1) L+S=22
And
2)4L=7S
From equation 1) we get L=22-S

Substitute this into equation 2) to get 4(22-S)=7S
88-4S=7S
88=11S
S=8. The smaller number is 8

As they total 22 the larger number is 14.
Check: 4x14=7x8. Yes

Solution 2:

Let x= larger number
And let y= smaller. umber

Now we are told that:
4x=7yeq1
We are also told that:
x + y=22eq2

Substitution method looks easier.

From eq1 x=(7/4)y. Substitute this into eq2
(7 /4)y +y=22
(7/4)y+(4/4)y=22
(11/4)y=22 multiply each side by 4
11y=88
y=8

From eq2, x+8=22
x=14

Hope this helps

answer: 2530

hope this

chiken

step-by-step explanation: