Will fan and medal a plane is located at c on the diagram. there are two towers located at a and b. the distance between the towers is 7,600 feet, and the angles of elevation are given. a. find bc, the distance from tower 2 to the plane, to the nearest foot. b. find cd, the height of the plane from the ground, to the nearest foot.

The complete question in the attached figure

Part A) Find BC, the distance from Tower 2 to the plane, to the nearest foot.

in the triangle ACD
sin16=CD/(7600+BD)--------> CD=sin16*(7600+BD)---------> equation 1
 
in the triangle BCD
sin24=CD/BD-----------> CD=sin24*BD---------------> equation 2

equation 1=equation 2
sin16*(7600+BD)=sin24*BD-----> sin16*7600+sin16*BD=sin24*BD
sin24*BD-sin16*BD=sin16*7600----> BD=[sin16*7600]/[sin24-sin16]
BD=15979 ft

in the triangle BCD
cos24=BD/BC---------> BC=BD/cos24-------> 15979/cos24-------> 17491
BC=17491 ft

the answer part 1) BC is 17491 ft

Part 2) Find CD, the height of the plane from the ground, to the nearest foot.

CD=sin24*BD        ( remember equation 2)
BD=15979 ft
CD=sin24*15979 -----------> CD=6499 ft

the answer part 2)  CD is 6499 ft

Where’s the stuff st? ? lol sorry