4. an airplane at t(80,20) needs to fly to both u(20,60) and v(110,85). what is the shortest possible distance for the trip? 165units 170units 97units 169 units is the answer a?

The distance formula for two points in a plane is 
D=sqrt( (x1-x2)^2 + (y1-y2)^2 ) 
 From T to U
 D= sqrt((80-20)^2 + (20-60)^2) = 72.11 
 Then flying from U to V
 D= sqrt((20-110)^2 + (60-85)^2) = 93.4 
 So T to U to V = 72.11+93.4 = 165.5 
 BUT checking also T to V to U
 From T to V
 D= sqrt((80-110)^2 + (20-85)^2) = 71.6
 Then from V to U
 D= sqrt((110-20)^2 + (85-60)^2) = 93.4 
 So from T to V to U = 165
 Pretty much the same both directions
 So yes the answer is A

44 % of 325 is 143

Dhope this