The length of a rectangle is 2 foot less than 3 times its width. find the the dimensions of this rectangle if the area is 96 square feet.

For example,area = a, length = l, width = w
First we write two equations. The easier equation is the area equation, which we know to be
a = l x w
So that the first equation is : 
96 = l x w 

we make the second equation of the following statements :
The length of a rectangle is 2 foot less than 3 times its width.
so it becomes :
l = 3w - 2

To solve, we can use the substitution method. 







So if our width is 6, Now substitute the value of w = 6 into equation 2 



So "w" = 6 and "l" = 16, and if we multiply them together, we get the correct area, 96. So our dimensions are 6 by 16.

Iknow one of the answers is a and maybe b but not 100% sure about b