Quadrilateral abcd is inscribed in circle o.

what is m∠b ?

enter your answer in the box.

1. The quadrilateral ABCD is inscribed in circle O, then, the sum of its opposite angles is 180°.

 2. As you can see, m∠A=2x-7 and m∠C=x+4 are opposite angles, then, you have:

 m∠A+m∠C=180°

 3. When you substitute the values of m∠A and m∠C into m∠A+m∠C=180°, you obtain:

 m∠A+m∠C=180°
 (2x-7)+(x+4)=180°

 4. You must clear the "x", as below:

 3x-3=180°
 3x=180°-3
 x=177°/3
 x=59°

 5. Now, you can substitute the value of "x" into m∠B=2x+3:

 m∠B=2x+3
 m∠B=2(59°)+3
 m∠B=118°+3
 m∠B=121°

 What is m∠B ? 

 The answer is: m∠B=121°

Hello!

the answer is:

the answer is:

why?

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!