Find three positive consecutive integers such that the product of the second integer and the third integer is 72

Let xbe a positive integer number. Then x, x+1 and x+2 are three positive consecutive integers (the first one is x, the second is x+1 and the third is x+2).

The product of the second integer and the third integer is (x+1)·(x+2) and is equal to 72. So you have the equation

Solve it:

Solution is extra because is negative.

three positive consecutive integers are 7, 8 and 9.

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step-by-step explanation: