Your parents have decided to buy a new toyota 4runner for 25,635. according to the dealer, the car will depreciate in value approximately $3,000 per year. write and solve a linear equation to find how many years it will be until the car is worth $3,135

Let the value of the car be represented by V and the amount of years by y. 
This gives us the following formula:
V = 25,635 - 3000y
(This is because we start with a value of $25,635 and the value decreases by $3,000 every year 'y')

Now, we want to know when the car is worth $3,135, so we know V = 3,135
Now we can make up our equation:
25,365 - 3,000y = 3,135

Collecting terms gives us:
-3,000y = -22,500

Finally we divide by -3,000 to find 'y'
y = -22,500 / -3,000 = 7.5

Hence, the car will be worth $3,135 after 7.5 years.

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

f(-2) = -3f(1) = 6 . . . estimated from f(x) = (x+2)^2-3, which matches points on the graph (-1,-2) and (0, 1)

so the change in y-value for function f is (6 )) = 9.

the table tells us

g(-2) = 1g(1) = 31

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

Yeah she/ he needs look how long that is man