What is the slope-intercept form of the equation of the line that passes through the point (–6, 1) and is perpendicular to the graph of 2x + 3y = –5? y = x – 8 y = x + 1 y = x + 1 y = x + 10

Step-by-step explanation:

Given equation of line :

Standard form of equation of line =  ---A

Where m is the slope

Convert the given equation in standard form

So, slope =

If the two lines are perpendicular then the product of their slopes is -1

Let n be the slope of required equation of line

So,

Substitute this value in A

 --B

Now we are given that the required perpendicular line passes through the point (–6, 1)

So, substitute  (–6, 1)  in B

Substitute the value of c in B

Hence the slope-intercept form of the equation of the line that passes through the point (–6, 1) and is perpendicular to the graph of 2x + 3y = –5? is  

plz mark brainliest i took the test

1) the property is   ixi = a ⇔x = a   o x = -a

4(x-5)+3= 15⇒4x-20+3 = 15⇒4x-17= 15⇒4x = 15+17⇒4x = 32⇒x =32/4= 8

4(x-5) +3= -15⇒4x-20 +3 = -15⇒4x-17= -15⇒4x =-15+17⇒4x = 2⇒x =2/4= 1/2

the values are x =8 and x = 0,5