Answers: 1
![a^\frac{m}{n}=\sqrt[n]{a^m}\\---------------\\\\(-0.008)^\frac{2}{3}=\sqrt[3]{(-0.008)^2}=\left(\sqrt[3]{-0.008}\right)^2=\left(-0.2\right)^2=0.04](/tpl/images/0177/2350/034c8.png)
![( \frac{-8}{1000} )^{ \frac{2}{3} } = \sqrt[3]{( \frac{-8}{1000})^{2} } = \sqrt[3]{ \frac{64}{1,000,000} }= \frac{4}{100}=0.04= \frac{2}{50}= \frac{1}{25}](/tpl/images/0177/2350/7a0c6.png)
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How do you solve this? pre calculus; (-0.008) ^2/3...
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