With the ones i circled for brainliest! you so much

1) Subtract the upper right 10 ft square from the overall 18 ft square.
.. (18 ft)^2 -(10 ft)^2 = 224 ft^2

3) The area of this is the sum of the areas of a rectangle 11 in by 7 in, and a triangle with base 7 in and height 5 in.
.. (11 in)*(7 in) +(7 in)*(5 in)
.. = (7 in)*(11 in +2.5 in) = 94.5 in^2

4) The central rectangle is 10 cm by 14 cm; the remaining triangle has a height of 7 cm and a base of 24 cm.
.. (10 cm)*(14 cm) +(24 cm)*(7 cm)/2
.. = 140 cm^2 +84 cm^2
.. = 224 cm^2

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm