Imagine that a lake contains two kinds of fish: trout and bass. 60% of the fish in the lake are bass and 40% are trout. if you caught 5 fish at random from this pond, which of the following would you expect to catch?
a. 0 bass and 5 trout
b. 2 bass and 3 trout
c. 3 bass and 2 trout
d. 5 bass and 0 trout

 c. 3 bass and 2 trout

Step-by-step explanation:

Given : There are two kinds of fish .

60% of the fish in the lake are bass and 40% are trout.

We can write 60% as 0.60.

If you caught 5 fish at random from this pond, then the expected number of fish in the lake are bass =

The expected number of fish in the lake are trout =

Hence, we expect to catch 3 bass and 2 trout.

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a