Mathematics, 30.07.2019 14:30, lisaxo

The length of a football field is 67 yards greater than the width the perimeter of the field is 346 yard. find the length and width of the football field.

Answers: 2

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Hey. Let me help you on this one.

In order for us to solve this question, we will need to set up an equation with an unknown variable. We will then solve for it, thus receiving everything we need for the width and length of the football field. I will also be attaching an image with all the work shown, so make sure to take a look at it.

First of all, let's identify our total in the equation. In this case, if we add both length and width together, we will get one half of 346 - the perimeter due to the fact that perimeter calls for both widths, and both lengths of a rectangle.

Let's form the equation which we will then solve.

2[x+(x+67)]=346

In this equation, x stands for the width. You can also see "x+67", which is the length of the rectangle. Both these values are added together, and multiplied by two. Let's start solving.

Let's simplify this equation.

4x+134=346

As you can see, we have multiplied the sum of all these numbers by two. Now, let's get rid of 134 on both sides.

4x=212

In that step, I have deducted 134 from both sides. Now, let's get rid of four on both sides by dividing it.

x=53

Awesome! As we know, "x" is the width. Now, knowing the width, we can find the length simply by adding 67 to the variable x since length is 67 yards longer than the width.

53+67=120

Great! Our answer is formed.

Length of the rectangle is 120 yards, and width of the rectangle is 53 yards.

The length of a football field is 67 yards greater than the width the perimeter of the field is 346

The length of a football field is 67 yards greater than the width the perimeter of the field is 346

answered: Guest

step-by-step explanation:

answered: Guest

answer:

total cost for tiles and paints is $924.

step-by-step explanation:

we have been given that a community hall is in the shape of a cuboid. the hall is 40m long 15m high and 3m wide.

the paint will be required for 4 walls and ceiling.

let us find area of walls and ceiling.

$\text{area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)$

$\text{area of walls and ceiling}=1200+90+120$

$\text{area of walls and ceiling}=1410$

therefore, the area of walls and ceiling is 1410 square meters.

given: cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. therefore,

$\text{ the total painting cost}=10*(\frac{1410}{25})$

$\text{ the total painting cost}=10*56.4=564$

therefore, the total painting cost is $564.

tiles will be required for floor. let us find the area of floor.

$\text{area of floor} = 40*3\text{ square meters}$

$\text{area of floor} =120\text{ square meters}$

given: 1m squared floor tiles costs $3. so,

$\text{total cost for tiles} = 3*120 = 360$

therefore, the total tiles cost is $360.

now let us find combined total cost of tiles and paint.

$\text{combined total cost}= 564+360 = 924$

therefore, the combined total cost of tiles and paint is $924.

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