What are the solutions of the system? y=6x+6y=−x2+5x+6

Given the system of equations:

        .....[1]

     .....[2]

Equate these two equations we have;

Subtract 6 from both sides we have;

Subtract 6x from both sides we have;

⇒

By zero product property we have;

⇒x = 0 and x+1= 0

⇒x = 0 and x=-1

Substitute these values in [1] we have;

For x = 0

y = 6(0)+6 = 6

for x = -1

y =6(-1)+6 = -6+6=  0

Therefore, the solutions of the given systems are, (0, 6) and (-1, 0)

cosine

step-by-step explanation:

ou would have 12 of each