The proof that hg ≅  eg  is shown. given: g is the midpoint of kf kh ∥  ef prove:   hg  ≅  eg what is the missing reason in the proof? statement reason 1. ∠egf ≅ ∠hgk 1. vert. ∠s are ≅ 2. kh ∥ ef 2. given 3. ∠f ≅ ∠k 3. alt. int. ∠s are ≅ 4. g is the midpoint of kf 4. given 5. fg ≅ kg 5. def. of midpt. 6. △feg ≅ △khg 6. ? 7. hg ≅ eg 7. cpctc sas asa aas hl

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

the answer is c.

step-by-step explanation: