The equation of a circle whose center is at (4, 0) and radius is length 2√(3) is (x - 4)² + y² = 2√3 (x - 4)² + y² = 12 (x + 4)² + y² = 12

Equation of the circle is

Step-by-step explanation:

We have been given that

center of the circle = (4,0)

Radius of the circle =

The standard form of a circle is given by

Here, (h,k) is the center and r is the radius. Thus, we have

h = 4, k = 0, r = 2√(3)

Substituting these values in the above equation, we get

Simplifying, we get

Therefore, equation of the circle is

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.