Describe the graph y=4[x+2] on [0, 3). be specific in your description.

 The description is mentioned in the below explanation.

Step-by-step explanation:

Since  greatest integer function rounds down a real number to the nearest integer. for example, if f(x)=[x] and for x =1.3 f(x)= [1.3]= 1

or x= 0.9 f(0.9)= [0.9]= 0

Here, The given function, y=4[x+2]

Which is a greatest integer function and it is described on  [0,3)

So, For the values of  ,we take  x=0 ⇒ y= 4(0+2)= 8

For,   , we take x=1, ⇒ y = 4(1+2)= 12

For,   we take x=2, ⇒ y = 4(2+2)=16

The graph description for the open or close interval, is mean describe values of variable for the interval. The graph is described and the values of y we get are 8,12, and 16 for the values of x as 0,1 and 2.

Integer keeps the values as positive or the negative and graphed at the number line.

Given information-

The function of the graph given in the problem is,

This function need to be describe on the points [0,3).

The close bracket is used in left side means the value 0 is included and the  open bracket is used in right side means the value 3 is excluded.

Thus find the value of variable y for the different intervals o x,

The interval is,

The graph of the given point is attached below.

Thus the graph is described and the values of y we get are 8,12, and 16 for the values of x as 0,1 and 2.

Learn more about the graph integer on a number line here;

link

l.jnl.j/n.m,lm,

step-by-step explanation:

hi! i think the answer is 1/2 : )