Big reward! (answer the right answer not just comment). 2(5x-4)=ax+b find a value for a and b so that the solution is a. has one solution b. has no solutions. c. infinite solutions

A. a = 0, b = 2

B. a = 10, b = 0

C. a = 10, b = -8

Step-by-step explanation:

2(5x-4)=ax+b

10x - 8 = ax + b

When a = 10, b = -8

This equation becomes true for all x. Hence infinite solutions.

When a = 10, b is not -8,

This equation has no solution.

One possible combination could be:

a = 10, b = 0

When a is not 10,

The two sides of the equation become two non parallel lines which will intersect at one point.

A combination could be:

a = 0, b = 2

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

idk

step-by-step explanation: