Which is the equation of the line that has a slope of 4 and passes through point (1,6)?

If I'm correct, it should be y = 4x + 2.

From the question, we get these informations.
m = 4
(x₁,y₁) = (1,6)

To determine the equation, use this following formula
y - y₁ = m(x - x₁)

Input the numbers
y - y₁ = m(x - x₁)
y - 6 = 4(x - 1)
y - 6 = 4x - 4
y = 4x - 4 + 6
y = 4x + 2
This is the line equation

Just a second zzz