Aboat in calm seas travels in a straight line and ends the trip 16 km west and 50 km north of its original position. find the direction of the trip to the nearest tenth of a degree.

Take the sin(∠boat)= side opposite the angle (50 km)/ (hypotenuse)
 sin(∠boat)= 50/52.5
(take the invers sin of (50/52.5)
∠boat= 80.3° North West

ANSWER:
The boat's traveled 80.3° North West

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.

The answer is 76° i believe