Write an equation for the line that is parallel to the given line and that passes through the given point. y = 2x + 7; (3, 11) i'm so bad at math

Parallel to y = 2x + 7, passes through (3, 11)

Alrighty, so remember : if an equation is parallel to another equation, then both of their slopes are the same. 

Identify the slope of our given line. Since our equation is in slope-intercept form, remember that "m" is the slope. Therefore, our slope is 2.

Now, plug in (3, 11) and "m" (2) into slope intercept form, y=mx+b. We're essentially just finding "b" which is our y-intercept.

y = mx+b

(11) = (2)(3) + b

Simplify.

11 = 6 + b

Subtract 6 from both sides.

11 - 6 = b

Therefore, b = 5

So now plug everything into our new equation.

Remember that our new equation has a slope of 2 and a y-intercept of 5.

y = mx+b

y = 2x + 5

~Hope I helped!~