If 9999 = 4, 8888 = 8, 1816 = 6, 1212 = 0, then 1919 =?

1919=2

Step-by-step explanation:

In,9999 there are four circles,one in each 9, therefore the answer is 4.

In,8888 there are eight circles, one in each 8,therefore the answer is 9.

Similarly, in 1816 and 1212, there are six and zero circles in each number. Hence the answer is 6 and 0 respectively.

Therefore, in 1919, following the above path, there will be 2 zeroes,one in each nine.

Hence, 1919=2

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt