Mathematics, 01.08.2019 21:00, lol6998

Are the product of 3/4×2/9 greater than 2/9 plz explain

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Less because if you multiply any number by a fraction (not mixed or improper) than it will always be less because multiplying it by 1 will keep it the same anything less than one will make the number smaller the answer of 3/4 x 2/9 is 1/6 btw

answered: Nicaragua505

Hey there!

Let's first multiply 3/4 and 2/9. When we multiply fractions, we multiply the numerators and denominators, so we have:

3/4 times 2/9 = 6/36 = 1/6

Now, we have to compare 1/6 and 2/9. In order to do this, we can multiply them both by a version of one to get equivalent fractions with the same denominator. This is because anything times one is itself, but we can keep it as itself, just with a different denominator, as I said. The least common multiple of the denominators are 18, so we multiply:

1/6(3/3) --> (3/3 equals one) = 3/18
2/9(2/2) = 4/18

Now that we have the same denominator, we can compare the numerators to see that 2/9 is actually greater.

Hope this helps!

answered: Guest

It’s will be 10 weeks

answered: Guest

5. y=6; de=7; fg=8

6. x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

y = 6

of course, the total chord length is the sum of the lengths of its segments.

de = dh +eh = 3+4 = 7

fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

x = lk = mk×nk/jk = 6×7/10 = 4.2

jl = jk +lk = 10 +4.2 = 14.2

mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.

Find the value of the variable and the length of each chord for #5 and #6.

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Are the product of 3/4×2/9 greater than 2/9 plz explain...