Find the area of the crescent-shaped region (called a lune) bounded by arcs of circles with radii r = 2 and r = 14

the complete question in the attached figure 

Let 

A1-------> half of the area of the blue circle
A2-------> area of the circular segment formed by the diameter of the blue circle treated as a chord of the red circle

A3---------- > area of the crescent-shaped region

A1=pi*2²/2=6.28

Area of the circular sector

if 360 º corresponds to an area of pi*14²

2*arc sin(2/14)------------------- X

X=16.43*pi*14²/360---------- > X=28.10

Triangle area:

------- >(4/2)*√(14²-2²=27.72 

Area of the circular segment A2=Area of the circular sector-Triangle area

A2=28.10-27.72=0.38

A3=  A1-A2=6.28-0.38=5.90 units²

the answer is 5.90 units²

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3