Anut mixture of walnuts and cashew nuts at a small fair is $1.00 per pound of walnuts and $4.19 per pound of cashew nuts. over the entire day, 121 pounds of the nut mixture were sold for $280.50. if p is the number walnuts and n is the number of cashew nuts, then the system of equations that models this scenario is: p+n=121p+4.19n=280.50

There are 71 walnuts and 50 cashew nuts.

Step-by-step explanation:

Since we have given that

Cost of per pound of walnuts = $1.00

Cost of per pound of cashew nuts = $4.19

Total number of pounds = 121

Total Amount for mixture = $280.50

Let the number of walnuts be 'p'.

Let the number of cashew nuts be 'n'.

According to question, it becomes,

By graphing method, we get that

We get that

p = 71  and n = 50

Hence, there are 71 walnuts and 50 cashew nuts.

water molecules will move from the side of higher water concentration to the side of lower concentration until both solutions are isotonic. at this point, equilibrium is reached. in an isotonic solution, the flow of water in and out of the cell is happening at the same rate.

hope this < 3

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: