Given the vertices are a (2,-5), b (-4,6) and c (3,1), find the vertices following each of the transformations from the original vertices: a. rx = 3 b. t< 3,-6> c. r(90◦, o)

A. rx = 3  this means reflect the vertices in the line x=3.x = 3 is a vertical line with an x-intercept of 3.when you reflect a point across the line, the distance between the original point and the line of reflection is the same as the distance between the transformed point and the line of reflection.a(2,-5) is one unit away from x = 3. on the other side of the vertical line x=3 should be the reflected point. this is     a'(4,-5)b(-4, 6) is 7 units away from x = 3 and it is to the left of x = 3. so x coordinate that is 7 units away from x = 3 to the right of x = 3 is 3 + 7 = 10. therefore this reflected point becomes    b'(10, 6) (the y-coordinate stays the same)c(3,1) is on the line of reflection, so it stays the same as      c'(3,1).b. t< 3,-6>   this means to translate the points 3 units right and 6 units down. add 3 to the x-coordinate; subtract 6 from the y-coordinate    a(2,-5) maps to a'(2 + 3, -5 - 6)  ⇒ a'(5, -11)    b(-4,6) maps to b'(-4 + 3, 6 - 6)  ⇒ b'(-1, 0)    c(3,1) maps to c'(3 + 3, 1 - 6)  ⇒ c'(6,-5)c. r(90◦, o)it says to rotate the points 90 degreesclockwise around/about the originrotation rule for 90° clockwise rotation about origin:     (a,b)  ⇒ (b, -a)so    a(2,-5) maps to a'(-5, -2)    b(-4,6) maps to b'(6, 4)    c(3,1) maps to c(1, -3)

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