Two buses leave a station at the same time and travel in opposite directions. one bus travels 16 /kmh faster than the other. if the two buses are 880km apart after 5 hours, what is the rate of each bus?

Let the speed of the slower bus be equal to x km/h
let the speed of the faster bus be equal to x+16 km/h
in one hour they are a further 2x+16 km apart
therefore after 5 hours they are 5(2x+16) = 10x + 80 km apart
10x + 80 = 880 km
10x = 800km
x = 80 
x + 16 = 96
therefore, the speed of the slower bus is 80 km/h whereas the speed of the second bus is 96 km/h

The equation is y=17(7)+600 and it equals 717