The table shows the position of a motorcyclist after accelerating from rest. find the average velocity for each time period: (2, 4)

The average velocity for each time period: (2, 4) is 29.3 ft/s

The table shows the position of a motorcyclist after accelerating from rest. find the average velocity for each time period: (2, 4)

The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is a vector quantity, then average velocity can be defined as the displacement divided by the time.

The average velocity over the time interval [t,t+h] is

First we obtain the average velocity over the time interval [2,4]

Then subsitute t=2 and t+h = 4 in equation v_avg above

From the table attached, we can know

When t=2 sec,

When t=4 sec,

Thus the average velocity over the time interval [2,4] is

Therefore the average velocity for each time period: (2, 4) is 29.3 ft/s

Grade:    5

Subject:  Math

Chapter:   the  velocity

Keywords: the average velocity, accelerating, position, motorcyclist, time period

the table in the attached figure

we need to find the average rates of change over each time interval

a)  [1, 3]    for t=1 seg  s=1.4 m  (1,1.4)  for t=3 seg  s=10.7 m  (3,10.7)

     v=(10.7-1.4)/(3-1)=9.3/2=4.65 m/seg

b)  [2, 3]    for t=2 seg  s=5.1 m  (2,5.1)  for t=3 seg  s=10.7 m  (3,10.7)

     v=(10.7-5.1)/(3-2)=5.6/1=5.6 m/seg      

c)  [3, 5]    for t=3 seg  s=10.7 m  (3,10.7)  for t=5 seg  s=25.8 m  (5,25.8)

     v=(25.8-10.7)/(5-3)=15.1/2=7.55 m/seg  

d)  [3, 4]    for t=3 seg  s=10.7 m  (3,10.7)  for t=4 seg  s=17.7 m  (4,17.7)

     v=(17.7-10.7)/(4-3)=7/1=7 m/seg  

15 batches are the most you can make

step-by-step explanation:

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.