It takes your garden hose 20 seconds to fill your 2-gallon watering can. how long will it take to fill a. an inflatable pool measuring 3 feet wide, 8 feet long, and 1 foot deep.14 b. a circular inflatable pool 13 feet in diameter and 3 feet deep.15

part (a):
Time taken to fill the pool = 1795.318706 seconds
part (b):
Time taken to fill the pool =  29771.99452 seconds

Explanation:
We are given that it takes 20 seconds to fill 2 gallons. Therefore, we can use cross multiplication to know how long will it take to fill one gallon as follows:
20 seconds > 2 gallons
?? seconds > 1 gallon
Time taken = (1*20) / 2 = 10 seconds
Therefore, it takes 10 seconds to fill one gallon of water.
One gallon is equivalent to 0.133681 ft^3
Therefore, it takes 10 seconds to fill 0.133681 ft^3.

Part (a):
volume of pool = length * width * height
volume of pool = 3 * 8 * 1
volume of pool = 24 ft^3
It takes 10 seconds to fill 0.133681 ft^3 of water, therefore:
10 seconds > 0.133681 ft^3
?? seconds > 24 gallons
Time taken to fill the pool = (24*10) / 0.133681 = 1795.318706 seconds

Part (b):
radius of pool = 13/2 = 6.5 ft
volume of pool = pi * (radius)^2 * height
volume of pool = pi * (6.5)^2 * 3 
volume of pool = 397.995 ft^3
It takes 10 seconds to fill one gallon of water, therefore:
10 seconds > 0.133681 ft^3
?? seconds > 397.995 ft^3
Time taken to fill the pool = (397.995*10) / 0.133681 = 29771.99452 seconds

Hope this helps :)

Ais right if u want more just write the common factors (the numbers that you multiply)