Worth 20 points if answered correctly. given: △abc, bd¯¯¯¯¯ bisects ∠abc prove: ad/dc = ab/bc statements reasons 1 △abc , bd¯¯¯¯¯ bisects ∠abc given 2 ∠aeb≅∠dbc (section a.) 3 ∠dbc≅∠abd definition of bisector 4 ∠aeb≅∠abd transitive property 5 ∠abd≅∠bae alternate interior angles theorem 6 ∠aeb≅∠bae (section b.) 7 ab = eb converse of isosceles base angle theorem 8 ad/dc = eb/bc (section c.) 9 ad/dc = ab/bc substitution property answer options: 1. transitive property 2. corresponding angles theorem 3. triangle proportionality theorem 4. alternate exterior angles theorem 5. angle addition postulate note: pick the answer number for which section it belongs to.

Given: △ABC,  segment BD bisects ∠ABC

StatementsReasons

1 △ABC , segment BD bisects ∠ABC(Given )

2 ∠AEB≅∠DBC seg (AE) ║seg DB so by Corresponding Angles Theorem    

3 ∠DBC≅∠ABD Definition of bisector

4∠AEB≅∠ABD  Transitive Property

5∠ABD≅∠BAEAlternate Interior Angles Theorem

6∠AEB≅∠BAE     Transitive Property  (If a = b and b = c then a =c)

7AB = EB Converse of Isosceles Base Angle Theorem

8 AD/DC = EB/BC Triangle Proportionality Theorem

9 AD/DC = AB/BC Substitution Property

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

sine

step-by-step explanation: