Write an equation perpendicular to x-4y= 20 that passes through the point (2, -5)

y + 5 = m(x - 2)  

Step-by-step explanation:

To write an equation of a new line perpendicular to x-4y= 20,  we need the slope of the original line first.  Solving this equation for y, we get x - 20 = 4y, or y = (1/4)x - 5.  The slope of the original line is 1/4.  The slope of a line perpendicular to the given line is the negative reciprocal of this 1/4, which turns out to be -4.

Now we have the slope (-4) of the desired new line, plus one point on this line, (2, -5).  Start with the point-slope form y - k = m(x - h).  Substitute 2 for h, -5 for k and -4 for m, obtaining:

y + 5 = m(x - 2)             This line is perpendicular to x-4y= 20.

answer: answer

step-by-step explanation:

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