Select the quadratic that has the roots x=8 and x=-5

this is correct beacuse

Step-by-step explanation:

x^2-3x-40

x^2-8x-5x-40

x(x-8)-5(x-8)

(x-8)(x-5)

the roots are

x=8 x=5

∞ this is your sign

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length