Arectangular patio has a perimeter of 60 feet. if the length of the patio is 3 feet less than twice the width, find the dimensions of the patio.

P = 2(L + W)
P = 60
L = 2W - 3

60 = 2(2W - 3 + W)
60 = 2(3W - 3)
60 = 6W - 6
60 + 6 = 6W
66 = 6W
66/6 = W
11 = W <=== the width is 11 ft

L = 2W - 3
L = 2(11) - 3
L = 22 - 3
L = 19 <=== the length is 19 ft

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