Tim and tom are painters. tim and tom are painting a crate. tom paints 10 sq ft per minute. they painted a particular crate in 1 day. tim uses a sprayer and is 3.5 times as fast as tom. how long would it take them to paint a crate with twice the volume and of similar shape? use the given information to provide the desired estimate. if necessary, enter the answer to the nearest hundredth.

Tim >3.5*10=35 sq ft per minute

 Both painters (10+35)=45 sq ft per minute

 let's assume a cubic unit crate> V1=1*1*1=1 feet3

the total surface of the cube is S1=6*(1*1)=6 sq ft

 if the volume of the cube increases twice 

V2=2 feet3 >    2=x*x*x >x=2^(1/3)

And the S2=6*(2^(1/3)* 2^(1/3)=9.5244 sq ft

V2/V1=9.5244/6=1.5874

Therefore

If Tim and Tom > take 1 day > to paint a crate V1

For the crate V2 > take 1.5874 days 

assuming an 8-hour work day

 0.5874*8=4.70 hr > 4 h 42 min

 The answer is 1 day 4h 42 min

step-by-step explanation:

my gg bhitch

b is the final answer! : )