See attachment and show work. you. will mark

a. Let c and b represent the numbers of capped and broken bottles, respectively. Here is the system of equations.

... c + b = 15 . . . . 15 bottles have come Erica's way

... 4c -2b = 6 . . . .Erica's net pay for the day is 6 cents

b. By substitution, we can write an expression for b in terms of c:

... b = 15 - c

Then put it into the second equation:

... 4c - 2(15-c) = 6

... 6c - 30 = 6 . . . . eliminate parentheses

... 6c = 36 . . . . . . .add 30

... c = 6 . . . . . . . . . divide by 6

... b = 15 - 6 = 9 . . find the value of b

Erica has capped 6 bottles and broken 9.

Here's one way to do it by elimination. We can divide the second equation by 2 to put it into standard form:

... 2c - b = 3

Now, adding it to the first equation gives

... (2c -b) + (c +b) = (3) + (15)

... 3c = 18 . . . . . simplify. Notice the b variable has been eliminated

... c = 6 . . . . . . . divide by 3

... 6 + b = 15

... b = 9 . . . . . . substitute into the first equation and solve for b by subtracting 6

Erica has capped 6 bottles and broken 9. (same solution as above)

range is infinite on both x and y axis positive and negative

step-by-step explanation: