Which theorem or postulate proves that △abc and △def are similar?

select from the drop-down menu to correctly complete the statement.

the two triangles are similar by the

SSS Similarity Theorem

Step-by-step explanation:

The answer is SSS Similarity Theorem because there is no angles labeled.

Hope this helps! ;)

From the given figure:

In triangle ABC

Side AB = 3 units, Side BC = 7 units and Side AC = 6 units.

In triangle DEF

Side DE = 18 units, Side EF = 42 units and Side DF = 36 units.

In triangle ABC and triangle DEF

⇒

SSS(Side-Side-Side) similarity theorem states that if three sides in one triangle are in same proportion to the corresponding sides of the other triangle, then these two triangles are similar

then, by SSS similarity theorem;

ΔABC ΔDEF

Therefore, the given two triangles are similar by SSS similarity theorem

answer: i believe c. is the answer sorry if i am wrong

step-by-step explanation:

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.