Ihave two cans of paint. can a has 9 parts of blue paint to one part of yellow paint. can b is 20 percent blue paint and the rest is yellow paint. how much paint should i use from each can to obtain 8 liters of paint which is half blue and half yellow.

of paint from Can A and of paint from Can B should be used to obtain of paint which is half blue and half yellow.

Let of paint from Can A and of paint from Can B should be used from each can to obtain of paint which is half blue and half yellow.

According to the question,

Can A has 9 parts of blue paint to one part of yellow paint and, Can B is blue paint and the rest is yellow paint so,

Therefore,

It is being given that the total volume of the final paint must be so,

And,

Hence, of paint from Can A and of paint from Can B should be used to obtain of paint which is half blue and half yellow.

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3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3