The number of fish in a lake decreased by 25% between last year and this year. last year there were 60 finish in the lake. what is the population this year?

Number of fish remaining this year will be 45.

Step-by-step explanation:

Given information:

The decrement in number of fish = 25%

Number of fish previous year = 60

Then , the remaining number of fish will be 75%

Hence ,

Hence, number of fish remaining this year will be 45.

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This population, the population is 45 fish.

Step-by-step explanation:

This problem can be solved by a rule of three.

Last year there were 60 fish in the lake. That was 100, that is, decimal 1.

This year it decreased 25%. So there 100%-25% = 75%, that is decimal 0.75. So

60 fish - 1

x fish - 0.75

This population, the population is 45 fish.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

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