Arectangle has length that is 4 inches longer than its width. it’s perimeter is 36 inches. which of the following is it’s area? a. 54 b. 64 c. 77 d. 81

C. 77

Step-by-step explanation:

Let l be length and w be the width of the rectangle,

Thus, the perimeter of the rectangle = 2 ( length + width )

= 2 ( l + w )

According to the question,

l - w = 4 ⇒ l = 4 + w

Also, 2(l+w)=36

2(4 + w +w)=36

4 + 2 w = 18

2w = 14

⇒ w = 7

So, the width of the rectangle is 7 inches.

And, length = 4 + 7 = 11 inches

Thus, the area of the rectangle = length × width

= 11 × 7

= 77 in²

Option 'C' is correct.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)